Q:

Solve each system of equations (systems with 3 variables)9x + 3y - 4z = 374x + 3y +7z = 16 x - 5y + 8z = -31​my answer is (2,5,-1)is that right?

Accepted Solution

A:
Answer:x = 2 , y = 5 , z = -1 You are correct!!!Step-by-step explanation:Solve the following system: {9 x + 3 y - 4 z = 37 | (equation 1) 4 x + 3 y + 7 z = 16 | (equation 2) x - 5 y + 8 z = -31 | (equation 3) Subtract 4/9 × (equation 1) from equation 2: {9 x + 3 y - 4 z = 37 | (equation 1) 0 x+(5 y)/3 + (79 z)/9 = (-4)/9 | (equation 2) x - 5 y + 8 z = -31 | (equation 3) Multiply equation 2 by 9: {9 x + 3 y - 4 z = 37 | (equation 1) 0 x+15 y + 79 z = -4 | (equation 2) x - 5 y + 8 z = -31 | (equation 3) Subtract 1/9 × (equation 1) from equation 3: {9 x + 3 y - 4 z = 37 | (equation 1) 0 x+15 y + 79 z = -4 | (equation 2) 0 x - (16 y)/3 + (76 z)/9 = (-316)/9 | (equation 3) Multiply equation 3 by 9/4: {9 x + 3 y - 4 z = 37 | (equation 1) 0 x+15 y + 79 z = -4 | (equation 2) 0 x - 12 y + 19 z = -79 | (equation 3) Add 4/5 × (equation 2) to equation 3: {9 x + 3 y - 4 z = 37 | (equation 1) 0 x+15 y + 79 z = -4 | (equation 2) 0 x+0 y+(411 z)/5 = (-411)/5 | (equation 3) Multiply equation 3 by 5/411: {9 x + 3 y - 4 z = 37 | (equation 1) 0 x+15 y + 79 z = -4 | (equation 2) 0 x+0 y+z = -1 | (equation 3) Subtract 79 × (equation 3) from equation 2: {9 x + 3 y - 4 z = 37 | (equation 1) 0 x+15 y+0 z = 75 | (equation 2) 0 x+0 y+z = -1 | (equation 3) Divide equation 2 by 15: {9 x + 3 y - 4 z = 37 | (equation 1) 0 x+y+0 z = 5 | (equation 2) 0 x+0 y+z = -1 | (equation 3) Subtract 3 × (equation 2) from equation 1: {9 x + 0 y - 4 z = 22 | (equation 1) 0 x+y+0 z = 5 | (equation 2) 0 x+0 y+z = -1 | (equation 3) Add 4 × (equation 3) to equation 1: {9 x+0 y+0 z = 18 | (equation 1) 0 x+y+0 z = 5 | (equation 2) 0 x+0 y+z = -1 | (equation 3) Divide equation 1 by 9: {x+0 y+0 z = 2 | (equation 1) 0 x+y+0 z = 5 | (equation 2) 0 x+0 y+z = -1 | (equation 3) Collect results: Answer:  {x = 2 , y = 5 , z = -1